4sin^2x+4=5

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Solution for 4sin^2x+4=5 equation: 


Simplifying
4sin2x + 4 = 5

Reorder the terms:
4 + 4in2sx = 5

Solving
4 + 4in2sx = 5

Solving for variable 'i'.

Move all terms containing i to the left, all other terms to the right.

Add '-4' to each side of the equation.
4 + -4 + 4in2sx = 5 + -4

Combine like terms: 4 + -4 = 0
0 + 4in2sx = 5 + -4
4in2sx = 5 + -4

Combine like terms: 5 + -4 = 1
4in2sx = 1

Divide each side by '4n2sx'.
i = 0.25n-2s-1x-1

Simplifying
i = 0.25n-2s-1x-1

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